Magic Sqaure of n order with C++

Magic Sqaure of n order with C++

3X3 Magic Sqaure

#include<iostream.h>

#include<conio.h>

void main()

{  clrscr();

int i,j,k,n,a[10][10],sum=0;;

cout<<"Enter a odd number \n";

cin>>n;

for(i=0;i<n;i++)

for(j=0;j<n;j++)

a[i][j]=0;

j=n/2;

k=0;

for(i=1;i<=n*n;i++)

{

if(k<0)k=n-1;

if(j>(n-1))j=0;

a[k][j]=i;

if(i%n==0)

++k;

else

{

--k;

++j;

}

} clrscr();

cout<<"Magic Square of "<<n<<"X"<<n<<" is as given:\n";

for(i=0;i<n;i++)

{

for(j=0;j<n;j++)

{

if(a[i][j]/10==0)cout<<" ";

cout<<a[i][j]<<" ";

}

cout<<"\n";

}for(j=0;j<n;j++)

sum+=a[0][j];

cout<<"\nWhere sum of all the elements of columns, rows and diagonal is "<<sum;

getch();

}

Happy Coding. 

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